x-2=(10x+19)^(1/2)

Solution for x-2=(10x+19)^(1/2) equation:

x-2=(10x+19)^(1/2)

We move all terms to the left:

x-2-((10x+19)^(1/2))=0

We add all the numbers together, and all the variables

x-((10x+19)^(+1/2))-2=0

We multiply all the terms by the denominator


x*2))-((10x+1+19)^(-2*2))=0

We add all the numbers together, and all the variables

x*2))-((10x+20)^(-4))=0

We add all the numbers together, and all the variables

x*2))-((10x=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$